[最も選択された] y=x^2 2x-8 in vertex form 289826

Suppose a parabola has a vertex (4,7) and also passes through the point (3,8) Write the equation of the parabola in vertex form f(x)=a(xh)^2k I believe h=4 k=7 Not sure what to do from here MathFrom this chart, we see that the parabola y = x 2 contains the points (3, 9) and (4, 16) On the other hand, he parabola y = 2x 2 contains the points (3, 18) and (4, 32) On the first equation, y =

Y=x^2 2x-8 in vertex form- heart 170 profile kim10g Answer The correct answer is y = 8 (x 2)^2 15 Stepbystep explanation I just got the question correctTiger shows you, step by step, how to solve YOUR Quadratic Equations 4(x1)^2=36^ by Completing the Square, Quadratic formula or, whenever possible, by FactoringFree factor calculator Factor quadratic equations stepbystepA) y = 2x 2 12x 16 B) y = 2x (x 6) 16 C) y = 2 (x 3) 2 (2) D) y = (x 2) (2x 8) Answer If you know the vertex form of an equation y = a (x h) 2 k then you will notice that

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